- 12000
- 4500
- 6000
- 7500
- To solve this, the other interest rate must also be given

Let the smaller amount be x and larger amount be 2x such that x > 1000.

So total money ( M ) = 3x .

Case 1: rate of interest on smaller amount = 10

rate of interest on larger amount = 5

Total interest received = (1.1^2 – 1)*x + (1.05^2 – 1)*2x = 0.21x + 0.205x

Given, 0.21x + 0.205x = 830

=> 415x = 830000

=>x= 2000

So M = 3x = 6000

Case 2:

rate of interest on smaller amount = 20

rate of interest on larger amount = 10

Total interest received = (1.2^2 – 1)*x+(1.1^2 – 1)*2x = 0.44x + 0.42x

Given, 0.44x+0.42x = 830=> x = 965.11

Which is not valid since x is greater than 1000

Thus M = 6000

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